limit of (xe^x - log(1 + x))/x^2 as x approaches 0 without application of L’Hospital’s Rule
In this video, we learn to find limit of (xe^x - log(1 + x))/x^2 as x approaches 0. The limit of (xe^x - log(1 + x))/x^2 as x approaches 0 is indeterminate form 0/0. To avoid this indeterminate form I have expanded e^x and log(1 + x). We can also apply the L’Hospital’s Rule to avoid this indeterminate form.
The following video explains to find the Taylor series expansion of e^x
• Taylor series of e^x
The following video explains to find the Taylor series expansion of log(1 + x)
• Taylor series of ln(1 + x)
Other topics of this video
Evaluate the limit as x approaches 0 of (xe^x - log(1 + x))/x^2
What is the limit of (xe^x - log(1 + x))/x^2 as x approaches 0
How to find the limit of (xe^x - log(1 + x))/x^2 as x approaches 0
Find limit of (xe^x - log(1 + x))/x^2 as x approaches 0
I, Ravi Ranjan Kumar Singh, have produced this video. All credits of this video belong to me.
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