We show the limit of sin(kx)/x as x goes to 0 is equal to k, even when k=0. To evaluate this trigonometric limit, we need to remember the limit of sin(x)/x with x approaching 0, which is a fundamental trigonometric limit equal to 1! If we remember this, we'll be able to solve the problem in short order by multiplying by k/k. #Calculus1 #apcalculus
Limit of sin(2x)/x as x approaches 0: • Limit of sin(2x)/x as x approaches 0 | Cal...
Proof for Limit of sin(x)/x: (coming soon):
Calculus 1 Exercises playlist: • Calculus 1 Exercises
Calculus 1 playlist: • Calculus 1
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